7/2-x=10-4x/x^2+3x-10

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Solution for 7/2-x=10-4x/x^2+3x-10 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

7/2-x = 3*x-((4*x)/(x^2))-10+10 // - 3*x-((4*x)/(x^2))-10+10

(4*x)/(x^2)-x-(3*x)+7/2-10+10 = 0

(4*x)/(x^2)-x-3*x+7/2-10+10 = 0

4*x^-1-4*x^1+7/2*x^0 = 0

(7/2*x^1-4*x^2+4*x^0)/(x^1) = 0 // * x^2

x^1*(7/2*x^1-4*x^2+4*x^0) = 0

x^1

(7/2)*x-4*x^2+4 = 0

(7/2)*x-4*x^2+4 = 0

DELTA = (7/2)^2-(-4*4*4)

DELTA = 305/4

DELTA > 0

x = ((305/4)^(1/2)-(7/2))/(-4*2) or x = (-(7/2)-(305/4)^(1/2))/(-4*2)

x = ((305/4)^(1/2)-7/2)/(-8) or x = ((305/4)^(1/2)+7/2)/8

x in { ((305/4)^(1/2)-7/2)/(-8), ((305/4)^(1/2)+7/2)/8}

x in { ((305/4)^(1/2)-7/2)/(-8), ((305/4)^(1/2)+7/2)/8 }

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